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-4.9x^2+8x-1.8=0
a = -4.9; b = 8; c = -1.8;
Δ = b2-4ac
Δ = 82-4·(-4.9)·(-1.8)
Δ = 28.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-\sqrt{28.72}}{2*-4.9}=\frac{-8-\sqrt{28.72}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+\sqrt{28.72}}{2*-4.9}=\frac{-8+\sqrt{28.72}}{-9.8} $
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